Asked by sh
Describe the effect on the concentration of the bold substance by the following change: decrease the volume
The equilibrium is: 2HF(g) <--> F2(g) + H2; change in H=536KJ
F2(g) is bolded.
Shouldn't F2(g) increase when voume is decreased? Why is there no change?
Thanks in advance.
The equilibrium is: 2HF(g) <--> F2(g) + H2; change in H=536KJ
F2(g) is bolded.
Shouldn't F2(g) increase when voume is decreased? Why is there no change?
Thanks in advance.
Answers
Answered by
bobpursley
you actually left out something very important:
2HF(g) <--> F2(g) + H2(g)
Hydrogen is a gas.
Notice that you have two volumes on the left, two volumes on the right at equilibrium. So reducing volume on both sides will have no effect on equilibrium.
2HF(g) <--> F2(g) + H2(g)
Hydrogen is a gas.
Notice that you have two volumes on the left, two volumes on the right at equilibrium. So reducing volume on both sides will have no effect on equilibrium.
Answered by
sh
So I have to count the number of gaseous molecules first? Thanks!
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