you actually left out something very important:
2HF(g) <--> F2(g) + H2(g)
Hydrogen is a gas.
Notice that you have two volumes on the left, two volumes on the right at equilibrium. So reducing volume on both sides will have no effect on equilibrium.
Describe the effect on the concentration of the bold substance by the following change: decrease the volume
The equilibrium is: 2HF(g) <--> F2(g) + H2; change in H=536KJ
F2(g) is bolded.
Shouldn't F2(g) increase when voume is decreased? Why is there no change?
Thanks in advance.
2 answers
So I have to count the number of gaseous molecules first? Thanks!