Both of them can be prepared in a beaker, however, the conc acid should be kunder a hood with a stirrer working.
a)massNaCL=58*.05*250*250
b) you are diluting it 15.8/3=5.27 times, which means 1 part conc acid, and 4.27 water.
Waht is one part?250/5.27=??? do that.
Now since acid has to be added to water, while stirring, put in the water in the beaker with the stirrer working, tha is 4.27*250/5.27 ml water, or 203 ml water.
then measure out in a gradusted cylinder the one part of conc acid, under the fume hood, wearing gloves, and eye protection 250/5.27=47ml of acid.
slowly pour the acid into the water, with vent on, and stirrer on.
Describe how you would prepare the following two solutions. Be sure to include the type of glassware which you would use and as much detail as necessary for someone to actually prepare the solution using good laboratory technique.
• 250 mLs of a 5% NaCl (w/v) from solid NaCl
• 250 mLs of 3 M HNO3 from concentrated nitric acid which is 15.8 M
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