describe how you would prepare 500ml of a solution containing 0.025M sodium acetate and 0.001% w/v starch.

1 answer

0.025M NaAc:
How many mols do you need? That M x L = mols. Then mol = grams/molar mass. You know molar mass and mols solve for grams.

0.001% w/v starch.
0.001g (1 mg) starch in 100 mL solution.