500.0 mL x 0.200M = xmL x 15.0M(although you didn't write M).
Solve for x and I get 6.667 mL. In practice you add 6.667 ml of the 15.0M NaOH to a 500.0 mL volumetric flask and add water to the mark on the flask. Note that you DO NOT add 6.667 mL NaOH to 493.3 mL H2O.
Describe how you would make 500.0mL of a 0.200M NaOH solution from a 15.0 stock NaOH conentration
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