Describe any number that satisfies BOTH inequalities: -3x < -9 and -3x < 9

Answer 1

To find a number that satisfies both inequalities, we can solve each one separately:

For the first inequality, -3x < -9, if we divide both sides by -3 (while keeping the inequality sign pointing in the same direction), we get:

x > 3

For the second inequality, -3x < 9, if we divide both sides by -3 (while keeping the inequality sign pointing in the same direction), we get:

x > -3

Since both inequalities have the same inequality (>) and the second inequality does not give any additional restrictions compared to the first one, any number greater than 3 will satisfy both inequalities.

For example:
- 4 satisfies both inequalities because it is greater than 3 and greater than -3.
- 5 satisfies both inequalities because it is greater than 3 and greater than -3.
- 10 satisfies both inequalities because it is greater than 3 and greater than -3.

In conclusion, any number greater than 3 will satisfy both -3x < -9 and -3x < 9.