To informally argue for the volume of a pyramid based on the volume of a cube, we can start by examining the relationships between the two shapes.
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Understanding the Cube:
A cube has a volume calculated by the formula \( V = \text{side}^3 \). If we know that the volume of our cube is 12 cubic meters, then we can find the dimensions of the cube. Let's say the side length of the cube is \( s \). Therefore, we have: \[ s^3 = 12 \text{ m}^3 \] The cube has equal sides. -
Base of the Pyramid:
A square-based pyramid shares the same base area as the top face of the cube. The base area of the pyramid is \( s^2 \), which equals the area of the square face of the cube (because it has the same side lengths). We can calculate the base area from the cube’s volume: \[ \text{Base Area} = s^2 \] -
Height of the Pyramid:
Since the pyramid has the same height as the cube, the height of the pyramid is \( s \), which is also the side length of the cube. -
Volume of the Pyramid:
The volume of a pyramid is given by the formula: \[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \] Substituting the base area and height of our pyramid, we have: \[ V = \frac{1}{3} \times s^2 \times s = \frac{1}{3} s^3 \] We already know from the volume of the cube that \( s^3 = 12 \text{ m}^3 \), so we can replace \( s^3 \): \[ V = \frac{1}{3} \times 12 \text{ m}^3 = 4 \text{ m}^3 \] -
Conclusion:
Therefore, the volume of the pyramid, which has the same base area and height as the cube, is \( 4 \) cubic meters.
From the options given, the correct answer is:
- 4 m³.