derivatives:

Question

y=(x^3+1)^2, then dy/dx is:

i got 6x^2(x^3+1) first but im not sure.
Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??

sorry for bugging.Thanks

Answer 1

y=(x^3+1)^2, then dy/dx is:

i got 6x^2(x^3+1) first but im not sure.
Can i see the steps of how it is done right. I also got 2(3x^2+1), which one is right??
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y' = 2(x^3+1)^1 dy/dx (x^3)

= 2 (x^3+1)(3)(x^2)

= 6 x^2 (x^3+1)