Derivative of y=in((e^-2x)(cos4x))

1 answer

y = ln((e^(-2x))(cos4x))
= ln(e^-2x) + ln(cos 4x)
= -2x + ln(cos 4x)

y' = -2 - 4sin4x/cos4x
= -2 - 4tan4x
Similar Questions
  1. y = (ln x)^(cos4x)Use logarithmic differentiation to find the derivative of the function.
    1. answers icon 1 answer
  2. Prove thatcos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x) then im kinda lost
    1. answers icon 2 answers
  3. Several questions from my homework, any are appreciated. Thanks!Solve: 1) sinx-tanx=0 2) 3csc^2x=4 Find all solutions within
    1. answers icon 0 answers
  4. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
    1. answers icon 1 answer
more similar questions