Asked by Anonymous
derivative of (4Cos^2(3x)+3)^2
Answers
Answered by
drwls
Multiply it out and differentiate it one term at a time. Multiplication results in
16 cos^4(3x) + 24 cos^2(3x) + 9
The derivative of the last term is zero.
Let u = cos (3x) and use the function of a function "chain rule" for the other two terms
The derivative of 24 cos^2(3x) (or 24 u^2) is
48 u du/dx = 48 cos(3x)*(-sin(3x))*3
= -144 sin(3x)cos(3x) = -72 sin(6x)
I leave the other term up to you.
16 cos^4(3x) + 24 cos^2(3x) + 9
The derivative of the last term is zero.
Let u = cos (3x) and use the function of a function "chain rule" for the other two terms
The derivative of 24 cos^2(3x) (or 24 u^2) is
48 u du/dx = 48 cos(3x)*(-sin(3x))*3
= -144 sin(3x)cos(3x) = -72 sin(6x)
I leave the other term up to you.
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