To find the inverse of the function \( f(x) = \frac{3x}{4} + \frac{1}{2} \), we will follow these steps:
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Replace \( f(x) \) with \( y \): \[ y = \frac{3x}{4} + \frac{1}{2} \]
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Swap \( x \) and \( y \): \[ x = \frac{3y}{4} + \frac{1}{2} \]
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Solve for \( y \):
- Subtract \( \frac{1}{2} \) from both sides: \[ x - \frac{1}{2} = \frac{3y}{4} \]
- Multiply both sides by 4 to eliminate the fraction: \[ 4\left(x - \frac{1}{2}\right) = 3y \] \[ 4x - 2 = 3y \]
- Now, divide by 3: \[ y = \frac{4x - 2}{3} \]
Thus, the inverse function is: \[ f^{-1}(x) = \frac{4x - 2}{3} \]
So, the correct response is:
f^−1(x)=4x−2/3
f inverse of x is equal to the fraction with numerator 4 x minus 2 and denominator 3