To identify the initial value, a, of the function f(x)=abx, we can substitute one of the given points into the equation and solve for a.
Let's substitute the point (1,6):
6 = a * b^1
6 = a * b
Now, to find the value of a, we need to use the second given point (2, 18):
18 = a * b^2
Now we have a system of equations:
6 = a * b
18 = a * b^2
Dividing the second equation by the first equation, we get:
18/6 = (a * b^2)/(a * b)
3 = b
Substituting this value of b back into the first equation, we can solve for a:
6 = a * 3
a = 6/3
a = 2
Therefore, the initial value, a, of the function is 2.
dentify the initial value, a of the function f(x)=abx
if its graph passes through the points (1,6) and (2, 18)(1 point)
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