dentify the initial value, a of the function f(x)=abx

Question

if its graph passes through the points (1,6) and (2, 18)(1 point)
Responses

4
4

3
3

2
2

5

Answer 1

To identify the initial value, a, of the function f(x)=abx, we can substitute one of the given points into the equation and solve for a.

Let's substitute the point (1,6):
6 = a * b^1
6 = a * b
Now, to find the value of a, we need to use the second given point (2, 18):
18 = a * b^2

Now we have a system of equations:
6 = a * b
18 = a * b^2

Dividing the second equation by the first equation, we get:
18/6 = (a * b^2)/(a * b)
3 = b

Substituting this value of b back into the first equation, we can solve for a:
6 = a * 3
a = 6/3
a = 2

Therefore, the initial value, a, of the function is 2.