To calculate the molar analytical concentration of Fe(NO3)3 in the solution, we first need to calculate the mass of Fe(NO3)3 present in 1 L of the solution.
Since the solution is 6.42% (w/w) Fe(NO3)3, we can assume there are 6.42g of Fe(NO3)3 in 100g of solution. Therefore, in 1 L of solution (which has a density of 1.059g/ml), there would be:
(6.42g Fe(NO3)3 / 100g solution) * 1.059g/ml * 1000ml/L = 67.99738g Fe(NO3)3/L solution
Now, we can calculate the molarity of Fe(NO3)3 in the solution:
Molarity = mass / (molar mass * volume)
Molarity = 67.99738g / (241.86g/mol * 1L) = 0.2807mol/L
Therefore, the molar analytical concentration of Fe(NO3)3 in the solution is 0.2807 mol/L.
Density and Specific Gravity of Solutions: Write the complete solutions:
A 6.42% (w/w) Fe(NO3)3 (241.86g/mol) solution has a density of 1.059g/ml. Calculate the molar analytical concentration of Fe(NO3)3 in the solution.
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