(a) The system that models the situation is:
- \( p + m = 5 \) (The total weight of the mixture is 5 lb)
- \( 0.6p + 0.2m = 3 \) (The total pounds of peanuts in the mixture should be 60% of 5 lb, which is 3 lb)
(b) We check each option:
-
2 lb peanuts and 3 lb mixture:
- \( p + m = 2 + 3 = 5 \) (True)
- \( 0.6(2) + 0.2(3) = 1.2 + 0.6 = 1.8\) (Not true)
-
2.5 lb peanuts and 2.5 lb mixture:
- \( p + m = 2.5 + 2.5 = 5 \) (True)
- \( 0.6(2.5) + 0.2(2.5) = 1.5 + 0.5 = 2.0\) (Not true)
-
4 lb peanuts and 1 lb mixture:
- \( p + m = 4 + 1 = 5 \) (True)
- \( 0.6(4) + 0.2(1) = 2.4 + 0.2 = 2.6\) (Not true)
None of the options provided are solutions to the system.