Dehydrate a primary alcohol containing 7 carbons.

General instructions:
1. Write out the reaction described. Include reactant(s), catalysts (you pick if there’s a choice), and product(s).
2. Draw condensed structures.
3. Write the specified common names or IUPAC ending when specified.

1 answer

The dehydration of a primary alcohol containing 7 carbons can be achieved through the E1 mechanism, using a strong acid catalyst such as concentrated sulfuric acid (H2SO4).

1. Reaction:
Primary alcohol (7 carbons) + concentrated sulfuric acid → alkene + water

2. Condensed structures:
Primary alcohol: R-CH2-CH2-CH2-CH2-CH2-CH2-OH
Concentrated sulfuric acid: H2SO4
Alkene: R-CH=CH-CH2-CH2-CH2-CH3
Water: H-OH

3. IUPAC naming:
The specified common name or IUPAC ending is not provided. Therefore, the IUPAC name of the alkene product would depend on the R group attached to the 7-carbon chain.