definite Integrals (using fundamental Theorem)

Question

definite Integrals (using fundamental Theorem)
 Evaluate
from -1 to 2(x^2 - 4x)dx

drwls · Answer

[x^3/3 - 2 x^2] @ 2 MINUS [x^3/3 - 2 x^2] @ -1 = [8/3 - 8] - [-1/3 -2] = -16/3 + 7/3 = -3

Stacy · Answer

Thank you so much. I had the integral part, but was off on the rest. :)