Define a function f(x)= {(x^2-9)/(x-3), if x≠3,

Question

{c, if x=3

What value of c makes f continuous at x=3?

Is the answer 1?

Answer 1

f(x)=
{(x^2-9)/(x-3), if x≠3,
{c, if x=3

Note that if x≠3, f(x) = x+3
so, you want f(3) = 6

Answer 2

Ohh I see, I've over-thought this question. Thanks for the help!