Let's use synthetic division to find the other factor of the polynomial.
1 │ 1 -2 -5 6
──────────────
1 -1 -6
───────────
1 -3 0
The remainder is 0, which means that (x - 1) is a factor of the polynomial. The quotient is x^2 - 3.
Therefore, the polynomial x^3 - 2x^2 - 5x + 6 can be decomposed as (x - 1)(x^2 - 3).
Decompose the polynomial x^3−2x^2−5x+6
into its linear factors, given that x−1
is a factor.
1 answer
1 answer