Ask a New Question

Decompose 58-x/x^2-6x-16 into partial fractions.

1 answer

If I wrote
(58 - x)/(x^2 - 6x - 16) as
= (58-x)/((x-8)(x+2))

can you follow the procedure I showed you in your post above this one?

Ask a New Question or answer this question.

Similar Questions

Is this right?Decompose into partial fractions. (2x^2-24x+35)/(x^2+2x-7)(x-2)= (Ax+B)/(x^2+2x-7)+C/(x-2)
1. 2 answers
5x+1/x^2(x^2+4) decompose into partial fractions
1. 3 answers
using method of partial fractions to decompose this 1/(x-3)(x+3)is 1/6(x-3)-1/6(x+3) correct or have i gone wrong somewhere
1. 2 answers
Decompose the following into partial fractions after factoring the denominator as much as possible. Please show some work so I
1. 3 answers

more similar questions