To determine which of the ordered pairs are solutions for the equation \( y = 4x + 2 \), we will substitute the \( x \) value of each ordered pair into the equation and check if the computed \( y \) value matches the \( y \) value given in the ordered pair.
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For the pair (-2, -6): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This matches the ordered pair, so (-2, -6) is a solution.
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For the pair (-1, 0): \[ y = 4(-1) + 2 = -4 + 2 = -2 \] This does not match, so (-1, 0) is not a solution.
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For the pair (-2, 6): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This does not match, so (-2, 6) is not a solution.
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For the pair (0, 2): \[ y = 4(0) + 2 = 0 + 2 = 2 \] This matches the ordered pair, so (0, 2) is a solution.
In summary, the ordered pairs that are solutions for the equation \( y = 4x + 2 \) are:
- (-2, -6)
- (0, 2)
3 answers