To determine which ordered pairs are solutions for the equation \( y = 4x + 2 \), we will substitute the x-value of each ordered pair into the equation to see if the resulting y-value matches the y-value of the ordered pair.
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For the pair \((-2, -6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This matches the given y-value, so \((-2, -6)\) is a Solution.
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For the pair \((-1, 0)\): \[ y = 4(-1) + 2 = -4 + 2 = -2 \] This does not match the given y-value, so \((-1, 0)\) is Not A Solution.
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For the pair \((-2, 6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This does not match the given y-value, so \((-2, 6)\) is Not A Solution.
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For the pair \((0, 2)\): \[ y = 4(0) + 2 = 0 + 2 = 2 \] This matches the given y-value, so \((0, 2)\) is a Solution.
To summarize:
- Solutions: \((-2, -6)\), \((0, 2)\)
- Not A Solutions: \((-1, 0)\), \((-2, 6)\)
19 answers