To determine which ordered pairs are solutions to the equation \( y = 4x + 2 \), we can substitute the \( x \) values from each ordered pair into the equation and check if the resulting \( y \) equals the \( y \) value given in the ordered pair.
-
For the pair \((-2, -6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This is a solution.
-
For the pair \((-1, 0)\): \[ y = 4(-1) + 2 = -4 + 2 = -2 \] This is not a solution (y should be 0).
-
For the pair \((-2, 6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This is not a solution (y should be 6).
-
For the pair \((0, 2)\): \[ y = 4(0) + 2 = 0 + 2 = 2 \] This is a solution.
So, based on the calculations:
- Solutions: \((-2, -6)\) and \((0, 2)\)
- Not Solutions: \((-1, 0)\) and \((-2, 6)\)
2 answers