Decide which of the ordered pairs are solutions for the equation y=4x+2

Question

.(4 points)
Solution Not A Solution
(−2, −6)

(−1, 0)

(−2,6)

(0, 2)

Answer 1

To determine if the ordered pairs are solutions of the equation \( y = 4x + 2 \), we will substitute the \( x \) values from each ordered pair into the equation and check if the resulting \( y \) value is equal to the \( y \) value in the ordered pair.

1. For the ordered pair \((-2, -6)\):

   • Substitute \( x = -2 \): \[ y = 4(-2) + 2 = -8 + 2 = -6 \]
   • Since \( y = -6 \) matches the ordered pair, this is a Solution.

2. For the ordered pair \((-1, 0)\):

   • Substitute \( x = -1 \): \[ y = 4(-1) + 2 = -4 + 2 = -2 \]
   • Since \( y = -2 \) does not match the ordered pair, this is Not A Solution.

3. For the ordered pair \((-2, 6)\):

   • Substitute \( x = -2 \): \[ y = 4(-2) + 2 = -8 + 2 = -6 \]
   • Since \( y = -6 \) does not match the ordered pair, this is Not A Solution.

4. For the ordered pair \((0, 2)\):

   • Substitute \( x = 0 \): \[ y = 4(0) + 2 = 0 + 2 = 2 \]
   • Since \( y = 2 \) matches the ordered pair, this is a Solution.

Summary:

• Solution: \((-2, -6)\) and \((0, 2)\)
• Not A Solution: \((-1, 0)\) and \((-2, 6)\)