To determine which ordered pairs are solutions for the equation \( y = 4x + 2 \), we need to substitute the x-value from each pair into the equation and see if it results in the corresponding y-value.
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For the pair \((-2, -6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This pair is a solution.
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For the pair \((-1, 0)\): \[ y = 4(-1) + 2 = -4 + 2 = -2 \] This pair is not a solution.
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For the pair \((-2, 6)\): \[ y = 4(-2) + 2 = -8 + 2 = -6 \] This pair is not a solution.
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For the pair \((0, 2)\): \[ y = 4(0) + 2 = 0 + 2 = 2 \] This pair is a solution.
In summary, the ordered pairs that are solutions for the equation \( y = 4x + 2 \) are:
- \((-2, -6)\)
- \((0, 2)\)
3 answers