Dean is hunting in the Northwest Territory at a location where the earth's magnetic field is 8.0x 10^-5 T. He shoots at a duck decoy by mistake, and the rubber bullet he is using acquires a charge of 3.0 x 10 ^ -12 C as it leaves his gun at 300m/s, perpendicular to the earth's magnetic field. What is the magnitude of the magnetic force acting on the bullet?

asked by Anonymous

7 years ago

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1 answer

F= qvB
= (3 x 10^-12 C)(300 m/s)(8.0 x 10^-5 T)
= ?

answered by Nonetheless

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Question

Dean is hunting in the Northwest Territory at a location where the earth's magnetic field is 8.0x 10^-5 T. He shoots at a duck decoy by mistake, and the rubber bullet he is using acquires a charge of 3.0 x 10 ^ -12 C as it leaves his gun at 300m/s, perpendicular to the earth's magnetic field. What is the magnitude of the magnetic force acting on the bullet?

1 answer

F= qvB
= (3 x 10^-12 C)(300 m/s)(8.0 x 10^-5 T)
= ?

Ask a New Question or answer this question.

Nonetheless · Answer

F= qvB = (3 x 10^-12 C)(300 m/s)(8.0 x 10^-5 T) = ?