The slope in this case would be 45 gallons per minute. The y-intercept (b value) would be 0, because there is no starting amount of water being discharged.
Now let's think about which graph best represents this rate. The graph should start at the origin (0,0) and have a steep slope of 45 gallons per minute.
Looking at the graph selections, the best choice would be a steep straight line that starts at the origin and has a slope of 45.
Therefore, the graph with a steep slope representing a rate of 45 gallons per minute is likely the correct choice.
Day 2–Proportional/Non-Proportional Cont.
Slope –How steep a line is. The “m” in y=mx + b. The rise/run or change in y/change in x.
**We also call this the rate of change.
We can find the slope from a graph, table or equation…
A water hose discharges water data rate of 45 gallons per minute. Which graph has a slope that best represents this rate?
Let’s think about this before even looking at the graph selections.
What is the slope (rate of change)? What is our “b” value (y-intercept)?
1 answer
1 answer