We can start by finding all possible combinations of length and width that give an area of 48 ft². These are:
1 ft x 48 ft
2 ft x 24 ft
3 ft x 16 ft
4 ft x 12 ft
6 ft x 8 ft
Next, we can calculate the perimeter for each of these combinations:
Perimeter of 1 ft x 48 ft pen = 2(1 ft + 48 ft) = 98 ft
Perimeter of 2 ft x 24 ft pen = 2(2 ft + 24 ft) = 52 ft
Perimeter of 3 ft x 16 ft pen = 2(3 ft + 16 ft) = 38 ft
Perimeter of 4 ft x 12 ft pen = 2(4 ft + 12 ft) = 32 ft
Perimeter of 6 ft x 8 ft pen = 2(6 ft + 8 ft) = 28 ft
Therefore, the possible perimeters are 52 ft, 38 ft, 32 ft, and 28 ft.
David wants to build a pen for his girl. He wants the area of the pan to be 48 ft.² if the length and width of the pen are whole numbers which of the following could be the perimeter of the pen
1 answer