By using the Pythagorean theorem (a^2 + b^2 = c^2), we can calculate the distance David is from his car.
a = 40 yards
b = 25 yards
c = √(40^2 + 25^2)
c = √(1600 + 625)
c = √(2225)
c ≈ 47.25 yards
Therefore, David is approximately 47.25 yards away from his car when he walks back in a straight line.
David runs out of gas so he gets out of his car and walks 40 yards north and 25 blocks yards east. How far is he from his car if he walked back in a straight line? F
1 answer