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David measures a line to be 10.3 in long. If the actual measurement is 10 in, find David's relative error to the nearest thousa...Asked by Maria Candea
David measures a line to be 8.9 in long. If the actual measurement is 9 in, find David's relative error to the nearest hundredth.
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Answered by
GPT-4o mini
To find David's relative error, we need to use the formula for relative error:
\[
\text{Relative Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{|\text{Actual Value}|}
\]
In this case, the measured value is 8.9 and the actual value is 9. Let's plug these values into the formula.
1. Calculate the absolute error:
\[
|\text{Measured Value} - \text{Actual Value}| = |8.9 - 9| = |-0.1| = 0.1
\]
2. Calculate the absolute value of the actual value:
\[
|\text{Actual Value}| = |9| = 9
\]
3. Now we can calculate the relative error:
\[
\text{Relative Error} = \frac{0.1}{9}
\]
4. Perform the division:
\[
\frac{0.1}{9} \approx 0.0111111
\]
5. Finally, round to the nearest hundredth:
\[
0.0111111 \approx 0.01
\]
Therefore, David's relative error to the nearest hundredth is:
\[
\boxed{0.01}
\]
\[
\text{Relative Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{|\text{Actual Value}|}
\]
In this case, the measured value is 8.9 and the actual value is 9. Let's plug these values into the formula.
1. Calculate the absolute error:
\[
|\text{Measured Value} - \text{Actual Value}| = |8.9 - 9| = |-0.1| = 0.1
\]
2. Calculate the absolute value of the actual value:
\[
|\text{Actual Value}| = |9| = 9
\]
3. Now we can calculate the relative error:
\[
\text{Relative Error} = \frac{0.1}{9}
\]
4. Perform the division:
\[
\frac{0.1}{9} \approx 0.0111111
\]
5. Finally, round to the nearest hundredth:
\[
0.0111111 \approx 0.01
\]
Therefore, David's relative error to the nearest hundredth is:
\[
\boxed{0.01}
\]
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