David measures a line to be 3.87 ft long. If the actual measurement is 4 ft, find David's relative error to the nearest hundredth.

1 answer

To find the relative error, we can use the formula:

\[ \text{Relative Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{|\text{Actual Value}|} \]

In this case, the measured value is 3.87 ft and the actual value is 4 ft. Plugging these values into the formula, we get:

\[ \text{Relative Error} = \frac{|3.87 - 4|}{|4|} \]

Calculating the absolute difference:

\[ |3.87 - 4| = |-0.13| = 0.13 \]

Now, divide this absolute difference by the actual value:

\[ \text{Relative Error} = \frac{0.13}{4} \]

Calculating this gives:

\[ \text{Relative Error} = 0.0325 \]

To express this as a percentage, we multiply by 100:

\[ \text{Relative Error} \times 100 = 0.0325 \times 100 = 3.25% \]

To the nearest hundredth, the relative error is:

\[ \boxed{0.03} \]

Thus, David's relative error, expressed as a decimal, is 0.03 (or 3.25% if expressed as a percentage).

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