The pencil holder is shaped like a triangular prism. To find the volume of the prism, we can use the formula V = 1/2 * b * h * l, where b is the base of the triangle, h is the height of the triangle, and l is the length of the prism.
For the given triangle, we have base b = 4 cm, height h = 3 cm, and length l = 10 cm.
Substitute these values into the formula:
V = 1/2 * 4 cm * 3 cm * 10 cm
V = 1/2 * 4 cm * 30 cm
V = 60 cm^3
Therefore, the volume of the pencil holder is 60 cubic centimeters.
Darlene bought the pencil holder shown
Triangle 6 cm 4 cm 10 cm
what is the volume of the pencil holder
11 answers
Jessica has just purchased a nee purse in the shape of a rectangular box to match her favorite shoes the purse has a length of 12 cm width of 5. 1 cm and height of 10 cm
To find the volume of the rectangular box purse, we use the formula for the volume of a rectangular prism which is given by:
Volume = length * width * height
Given that the length is 12 cm, the width is 5.1 cm, and the height is 10 cm, we can substitute these values into the formula:
Volume = 12 cm * 5.1 cm * 10 cm
Volume = 612 cubic centimeters
Therefore, the volume of Jessica's new purse in the shape of a rectangular box is 612 cubic centimeters.
Volume = length * width * height
Given that the length is 12 cm, the width is 5.1 cm, and the height is 10 cm, we can substitute these values into the formula:
Volume = 12 cm * 5.1 cm * 10 cm
Volume = 612 cubic centimeters
Therefore, the volume of Jessica's new purse in the shape of a rectangular box is 612 cubic centimeters.
Esma has a box that is 20 cm wide 10 cm high and 10 cm deep she wants to fill the box with packages that are 5 cm wide 2 cm high and 2 cm deep
what is the greatest number of packages that she can put in the box without it overflowing enter the answer in the box
what is the greatest number of packages that she can put in the box without it overflowing enter the answer in the box
To calculate the number of packages that Esma can place in the box, we need to find the volume of the box and the volume of each package. Then, we divide the volume of the box by the volume of the package.
Volume of the box:
Volume = length * width * height
Volume = 20 cm * 10 cm * 10 cm
Volume = 2000 cubic centimeters
Volume of each package:
Volume = length * width * height
Volume = 5 cm * 2 cm * 2 cm
Volume = 20 cubic centimeters
Now, to find the maximum number of packages that can fit in the box:
Number of packages = Volume of the box / Volume of each package
Number of packages = 2000 cubic centimeters / 20 cubic centimeters
Number of packages = 100
Therefore, Esma can fit a maximum of 100 packages in the box without it overflowing.
Volume of the box:
Volume = length * width * height
Volume = 20 cm * 10 cm * 10 cm
Volume = 2000 cubic centimeters
Volume of each package:
Volume = length * width * height
Volume = 5 cm * 2 cm * 2 cm
Volume = 20 cubic centimeters
Now, to find the maximum number of packages that can fit in the box:
Number of packages = Volume of the box / Volume of each package
Number of packages = 2000 cubic centimeters / 20 cubic centimeters
Number of packages = 100
Therefore, Esma can fit a maximum of 100 packages in the box without it overflowing.
3/8 ( 2x - 3)m= 1/4 - x
To solve the equation \(\frac{3}{8}(2x-3)\)=\(\frac{1}{4}\)-x, we first simplify both sides:
\(\frac{3}{8}(2x-3)\)=\(\frac{1}{4}\)-x
Multiply both sides by 8 to get rid of the fraction on the left side:
3(2x-3)=2-8x
Expand the left side:
6x-9=2-8x
Combine like terms:
6x+8x=2+9
14x=11
Divide by 14 on both sides:
\(x=\frac{11}{14}\)
Therefore, the solution to the equation is \(x=\frac{11}{14}\).
\(\frac{3}{8}(2x-3)\)=\(\frac{1}{4}\)-x
Multiply both sides by 8 to get rid of the fraction on the left side:
3(2x-3)=2-8x
Expand the left side:
6x-9=2-8x
Combine like terms:
6x+8x=2+9
14x=11
Divide by 14 on both sides:
\(x=\frac{11}{14}\)
Therefore, the solution to the equation is \(x=\frac{11}{14}\).
f (x) = x3 - 1
The function f(x) = x^3 - 1 represents a cubic function. This function takes an input value x, cubes it, and then subtracts 1 from the result.
For example, if we want to find the value of f(x) when x = 2:
f(2) = 2^3 - 1
f(2) = 8 - 1
f(2) = 7
Therefore, the value of the function f(x) at x = 2 is 7.
You can plug in any value of x into the function f(x) = x^3 - 1 to evaluate the function at that specific point.
For example, if we want to find the value of f(x) when x = 2:
f(2) = 2^3 - 1
f(2) = 8 - 1
f(2) = 7
Therefore, the value of the function f(x) at x = 2 is 7.
You can plug in any value of x into the function f(x) = x^3 - 1 to evaluate the function at that specific point.
(2a^2b)^3
To simplify the expression (2a^2b)^3, we need to raise each term inside the parentheses to the power of 3:
(2a^2b)^3 = 2^3 * (a^2)^3 * b^3
= 8 * a^(2*3) * b^3
= 8 * a^6 * b^3
Therefore, the simplified form of (2a^2b)^3 is 8a^6b^3.
(2a^2b)^3 = 2^3 * (a^2)^3 * b^3
= 8 * a^(2*3) * b^3
= 8 * a^6 * b^3
Therefore, the simplified form of (2a^2b)^3 is 8a^6b^3.
5 answers