Question

DaQuan marks two points on the coordinate plane. One point is L(4,2) and the other point is M(7,6) . What is the correct way for DaQuan to set up the distance formula?(1 point) Responses d=(2−7)2+(4−6)2−−−−−−−−−−−−−−−√ d is equal to square root of open paren 2 minus 7 close paren squared plus open paren 4 minus 6 close paren squared end root d=(6−7)2+(2−4)2−−−−−−−−−−−−−−−√ d is equal to square root of open paren 6 minus 7 close paren squared plus open paren 2 minus 4 close paren squared end root d=(4−7)2+(2−6)2−−−−−−−−−−−−−−−√ d is equal to square root of open paren 4 minus 7 close paren squared plus open paren 2 minus 6 close paren squared end root d=(2−4)2+(6−7)2−−−−−−−−−−−−−−−√

Answer 1

To set up the distance formula correctly between the two points \( L(4, 2) \) and \( M(7, 6) \), we use the distance formula:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Here, \( (x_1, y_1) \) represents point L, and \( (x_2, y_2) \) represents point M.

Plugging in the coordinates:

• \( x_1 = 4, y_1 = 2 \) (from point L)
• \( x_2 = 7, y_2 = 6 \) (from point M)

The correct setup is:

\[ d = \sqrt{(7 - 4)^2 + (6 - 2)^2} \]

Which evaluates to:

\[ d = \sqrt{(4 - 7)^2 + (2 - 6)^2} \]

Thus, the correct response from the provided options is:

d = \sqrt{(4 - 7)^2 + (2 - 6)^2}