Combinations:
1 c = 1 c
2 c = 2 c
3 c = 1 c + 2 c
4 c = 2 c + 2 c
5 c = 5 c
6 c = 1 c + 5 c
7 c = 1 c + 2 c
8 c = 1 c + 2 c + 5 c
9 c = 2 + 2 c + 5 c
Prices 1c to 9c she can cover with the minimum number of coins:
1 x 1c , 2 x 2c and 1 x 5c
10 c = 10 c
20 c = 20 c
30 c = 10 c + 20 c
40 c = 20 c + 20 c
50 c = 50 c
60 c = 10 c +50 c
70 c = 20 + 50 c
80 c = 10 c + 20 c + 50 c
90 c = 20 c + 20 c + 50 c
Prices 10c to 90c she can cover with the minimum number of coins:
1 x 10c , 2 x 20c and 1 x 50c
For prices $1 1c to $1 99c she can cover with the minimum number of coins:
1 x $ 1 + 1 x 1c + 2 x 2c + 1 x 5c + 1 x 10c + 2 x 20c + 1 x 50c
For prices $2 to $2 99c she must have:
1 x $ 2 + 1 x 1c + 2 x 2c + 1 x 5c + 1 x 10c + 2 x 20c + 1 x 50c
For prices $1 1 c to $2 99 c the minimum number of coins she must carry:
1 x $1 + 1 x $2 + 1 x 1c + 2 x 2c + 1 x 5c + 1 x 10c + 2 x 20 c + 1 x 50 c
Total 10 coins.
Dani is about to travel on a bus, and she knows she must tender the exact fare. She is not sure what this is, but she knows it is greater than $1 and less than $3. What is the minimum number of coins she must carry to be sure of carrying the correct fare? (Assume that the available coins are 1c, 2c, 5c, 10c, 20c, 50c, $1 and $2)
1 answer