Damien made a symmetrical origami fox using a right-angled triangular paper AED. AE = ED = 14 cm and BE = CE. The area of triangle BCE is 2 times that of triangle CDE. He then folded the 2 corners of the triangle to the back and formed the fox below. After folding, of triangle CDE was hidden.

Answer 1

The first step is to determine the dimensions of triangle BCE and triangle CDE.

Since triangle BCE has an area 2 times that of triangle CDE, we can write the following equation:
Area of BCE = 2 * Area of CDE

Let the height of triangle BCE be h and the base be x. The height of triangle CDE is the same as the height of triangle BCE, so h = 14 cm.

This gives us the equation for the areas of the two triangles:
(1/2) * x * h = 2 * (1/2) * 14 * x/2
=> (1/2) * x * 14 = 2 * (1/2) * 14 * x/2
=> 7x = 14
=> x = 2 cm

Now that we have the base of triangle BCE, we can calculate its area:
Area of BCE = (1/2) * 2 * 14 = 14 cm^2

Since the area of a triangle is given by (1/2) * base * height, the area of triangle CDE is:
Area of CDE = (1/2) * 14 * 2 = 14 cm^2

Now, we know that Damien folded the 2 corners of triangle CDE to the back and formed the fox below, hiding 1/3 of triangle CDE. This means that after folding, 2/3 of triangle CDE is visible.

2/3 * 14 = 28/3 ≈ 9.33 cm^2 of triangle CDE is visible.

Therefore, 4.67 cm^2 of triangle CDE was hidden after folding.