Question
D. Create your own geometric sequence. List at least six terms of your sequence.
Explain what makes it geometric.
E. Write a recursive formula for your geometric sequence.
F. Write an explicit formula for your geometric sequence. Use your explicit
formula to find the 100th term of your sequence.
Explain what makes it geometric.
E. Write a recursive formula for your geometric sequence.
F. Write an explicit formula for your geometric sequence. Use your explicit
formula to find the 100th term of your sequence.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
### D. Creating a Geometric Sequence
Let’s create a geometric sequence where the first term is \( a = 3 \) and the common ratio \( r = 2 \).
The sequence can be listed as follows:
1. First term: \( a_1 = 3 \)
2. Second term: \( a_2 = a_1 \cdot r = 3 \cdot 2 = 6 \)
3. Third term: \( a_3 = a_2 \cdot r = 6 \cdot 2 = 12 \)
4. Fourth term: \( a_4 = a_3 \cdot r = 12 \cdot 2 = 24 \)
5. Fifth term: \( a_5 = a_4 \cdot r = 24 \cdot 2 = 48 \)
6. Sixth term: \( a_6 = a_5 \cdot r = 48 \cdot 2 = 96 \)
So, the sequence is: **3, 6, 12, 24, 48, 96**
This sequence is geometric because each term after the first is found by multiplying the previous term by a constant (in this case, the common ratio \( r = 2 \)).
### E. Recursive Formula
The recursive formula for a geometric sequence can be written as:
\[
a_n = a_{n-1} \cdot r
\]
where:
- \( a_1 = 3 \) (the first term),
- \( r = 2 \) (the common ratio).
Thus, the recursive formula for our sequence is:
\[
\begin{align*}
a_1 &= 3 \\
a_n &= a_{n-1} \cdot 2 \quad \text{for } n > 1
\end{align*}
\]
### F. Explicit Formula
The explicit formula for a geometric sequence can be written as:
\[
a_n = a \cdot r^{n-1}
\]
For our sequence, this gives us:
\[
a_n = 3 \cdot 2^{n-1}
\]
To find the 100th term (\( a_{100} \)), we substitute \( n = 100 \) into the explicit formula:
\[
a_{100} = 3 \cdot 2^{100-1} = 3 \cdot 2^{99}
\]
Calculating this value:
\[
2^{99} \approx 6.338 \times 10^{29} \quad (\text{as an approximation})
\]
Thus,
\[
a_{100} \approx 3 \cdot (6.338 \times 10^{29}) \approx 1.9014 \times 10^{30}
\]
So, the 100th term of the sequence is approximately \( 1.9014 \times 10^{30} \).
Let’s create a geometric sequence where the first term is \( a = 3 \) and the common ratio \( r = 2 \).
The sequence can be listed as follows:
1. First term: \( a_1 = 3 \)
2. Second term: \( a_2 = a_1 \cdot r = 3 \cdot 2 = 6 \)
3. Third term: \( a_3 = a_2 \cdot r = 6 \cdot 2 = 12 \)
4. Fourth term: \( a_4 = a_3 \cdot r = 12 \cdot 2 = 24 \)
5. Fifth term: \( a_5 = a_4 \cdot r = 24 \cdot 2 = 48 \)
6. Sixth term: \( a_6 = a_5 \cdot r = 48 \cdot 2 = 96 \)
So, the sequence is: **3, 6, 12, 24, 48, 96**
This sequence is geometric because each term after the first is found by multiplying the previous term by a constant (in this case, the common ratio \( r = 2 \)).
### E. Recursive Formula
The recursive formula for a geometric sequence can be written as:
\[
a_n = a_{n-1} \cdot r
\]
where:
- \( a_1 = 3 \) (the first term),
- \( r = 2 \) (the common ratio).
Thus, the recursive formula for our sequence is:
\[
\begin{align*}
a_1 &= 3 \\
a_n &= a_{n-1} \cdot 2 \quad \text{for } n > 1
\end{align*}
\]
### F. Explicit Formula
The explicit formula for a geometric sequence can be written as:
\[
a_n = a \cdot r^{n-1}
\]
For our sequence, this gives us:
\[
a_n = 3 \cdot 2^{n-1}
\]
To find the 100th term (\( a_{100} \)), we substitute \( n = 100 \) into the explicit formula:
\[
a_{100} = 3 \cdot 2^{100-1} = 3 \cdot 2^{99}
\]
Calculating this value:
\[
2^{99} \approx 6.338 \times 10^{29} \quad (\text{as an approximation})
\]
Thus,
\[
a_{100} \approx 3 \cdot (6.338 \times 10^{29}) \approx 1.9014 \times 10^{30}
\]
So, the 100th term of the sequence is approximately \( 1.9014 \times 10^{30} \).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.