Asked by Rosalie
(d+8/d-9)divided by 9d+72/c-7
Can anyone point me in the right direction to solving this problem? Thank you
Can anyone point me in the right direction to solving this problem? Thank you
Answers
Answered by
bobpursley
Your nonuse of grouping symbols is annoying.
I think you meant this:
(d+8)/(d-9) divided by (9d+72)/(c-7)
well, multiplication is reciprocal of division, so your problem becomes
(d+8)/(d-9) multiplied by (c-7)/(9d-72)
or
(d+8)(9d-72)/((d-9)(c-7) or
9(d+8)(d-9)/((d-9)(c-7)) or
9(d+8)/(c-7)
I think you meant this:
(d+8)/(d-9) divided by (9d+72)/(c-7)
well, multiplication is reciprocal of division, so your problem becomes
(d+8)/(d-9) multiplied by (c-7)/(9d-72)
or
(d+8)(9d-72)/((d-9)(c-7) or
9(d+8)(d-9)/((d-9)(c-7)) or
9(d+8)/(c-7)
Answered by
Rosalie
Thank you for your help sir.
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