Cylinder has a radius of 6 and a height of 15. Cone has a radius of 6 and the height of 15. The sphere has a radius of 6. Which figures have a volume greater than 600 cubic inches? Choose all that apply. Use 3.14 for pi. Show your work. (2 points) Cylinder Cylinder Cone Cone Sphere

1 answer

To determine which figures have a volume greater than 600 cubic inches, we'll calculate the volume of each figure using the given dimensions and the formula for the volume of each shape.

  1. Volume of the Cylinder: The formula for the volume \( V \) of a cylinder is: \[ V = \pi r^2 h \] where \( r \) is the radius and \( h \) is the height. Given \( r = 6 \) and \( h = 15 \): \[ V = 3.14 \times (6^2) \times 15 \] \[ V = 3.14 \times 36 \times 15 \] \[ V = 3.14 \times 540 \] \[ V = 1695.6 \text{ cubic inches} \]

  2. Volume of the Cone: The formula for the volume \( V \) of a cone is: \[ V = \frac{1}{3} \pi r^2 h \] Given \( r = 6 \) and \( h = 15 \): \[ V = \frac{1}{3} \times 3.14 \times (6^2) \times 15 \] \[ V = \frac{1}{3} \times 3.14 \times 36 \times 15 \] \[ V = \frac{1}{3} \times 3.14 \times 540 \] \[ V = \frac{1}{3} \times 1696.2 \] \[ V = 565.2 \text{ cubic inches} \]

  3. Volume of the Sphere: The formula for the volume \( V \) of a sphere is: \[ V = \frac{4}{3} \pi r^3 \] Given \( r = 6 \): \[ V = \frac{4}{3} \times 3.14 \times (6^3) \] \[ V = \frac{4}{3} \times 3.14 \times 216 \] \[ V = \frac{4}{3} \times 678.24 \] \[ V = 902.99 \text{ cubic inches} \]

Summary of Volumes:

  • Cylinder: \( 1695.6 \) cubic inches
  • Cone: \( 565.2 \) cubic inches
  • Sphere: \( 904.32 \) cubic inches

Conclusion:

Figures with a volume greater than 600 cubic inches are:

  • Cylinder (1695.6 cubic inches)
  • Sphere (904.32 cubic inches)

The Cone does not exceed 600 cubic inches with its volume of \( 565.2 \) cubic inches.

Final Answer: Cylinder, Sphere