Cyclopropane, C3H6, is converted to its isomer propylene, CH2=CHCH3, when heated. The rate law is first order in cyclopropane, and the rate constant is 6.0 10^-4 /s at 500°C. If the initial concentration of cyclopropane is 0.0238 mol/L, what is the concentration after 719 s?

Question

Cyclopropane, C3H6, is converted to its isomer propylene, CH2=CHCH3, when heated. The rate law is first order in cyclopropane, and the rate constant is 6.0  10^-4 /s at 500°C. If the initial concentration of cyclopropane is 0.0238 mol/L, what is the concentration after 719 s?

DrBob222 · Answer

ln(No/N) = kt ln(0.0238/N) = 6.0E-4*719 N = ?