Asked by Busola

CuCO3=CuO +CO2.
Find the mass of 1mole of each substance taking part in the reaction. (Ar:Cu=64,C=12,O=16).
When 31g of CuCO3 is used;
1)how many grams of CO2 is formed.
2) what mass of solid remains after heating.
Answered by Damon
CuCO3 = 64+12+48 g/mol = 124 g
31/124 = .25 mol

CO2 = 12+32 = 44 g/mol
so 11 g for .25 mol

for CuO, subtract:)
31-11 = 20 grams

check:
CuO = 64+16 = 80 g/mol
.25*80 = 20 grams sure enough
Answered by Kayboo
Where does number 31 comes from?
Answered by Twisha
31 is given in the qn
Answered by Anonymous
What about answer number 2?
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