CuCO3=CuO +CO2.

Question

Find the mass of 1mole of each substance taking part in the reaction. (Ar:Cu=64,C=12,O=16).
When 31g of CuCO3 is used;
1)how many grams of CO2 is formed.
2) what mass of solid remains after heating.

Answer 1

CuCO3 = 64+12+48 g/mol = 124 g
31/124 = .25 mol

CO2 = 12+32 = 44 g/mol
so 11 g for .25 mol

for CuO, subtract:)
31-11 = 20 grams

check:
CuO = 64+16 = 80 g/mol
.25*80 = 20 grams sure enough

Answer 2

Where does number 31 comes from?

Answer 3

31 is given in the qn

Answer 4

What about answer number 2?