cubed √-72 simplified

1 answer

To simplify the expression \(\sqrt[3]{-72}\), we can start by factoring \(-72\).

First, we can rewrite \(-72\) as:

\[ -72 = -1 \times 72 \]

Next, we can further factor \(72\):

\[ 72 = 8 \times 9 = 8 \times (3^2) \]

Since \(8\) is a perfect cube (\(2^3\)), we can express \(-72\) as:

\[ -72 = -1 \times 2^3 \times 3^2 \]

Now we can use the property of cube roots that states:

\[ \sqrt[3]{a \times b} = \sqrt[3]{a} \times \sqrt[3]{b} \]

Applying this to our expression, we have:

\[ \sqrt[3]{-72} = \sqrt[3]{-1} \times \sqrt[3]{2^3} \times \sqrt[3]{3^2} \]

Calculating each component:

  • \(\sqrt[3]{-1} = -1\)
  • \(\sqrt[3]{2^3} = 2\)
  • \(\sqrt[3]{3^2} = 3^{2/3} = 3^{2/3} = \sqrt[3]{9}\)

Now we can combine these results:

\[ \sqrt[3]{-72} = -1 \times 2 \times \sqrt[3]{9} = -2 \sqrt[3]{9} \]

So, the simplified form of \(\sqrt[3]{-72}\) is:

\[ \sqrt[3]{-72} = -2 \sqrt[3]{9} \]