cube root of (-64x^8y^5)

Question

Is it -8x^2y times the cube of y^2?

Answer 1

-64 = -4*-4*-4 = -4^3

(x^8)^1/3 = x^(8/3)

(x^5)^(1/3) = x^(5/3

-4 x^(8/3) y^(5/3)

Answer 2

not quite

∛-64 = -4 (8 is √64)
also, you need to divide both exponents by 3. 8=3*2+2 and 5=3+2
so, the answer is

-4x^2y ∛(x^2y^2)