cube root of (-64x^8y^5)

Is it -8x^2y times the cube of y^2?

2 answers

-64 = -4*-4*-4 = -4^3

(x^8)^1/3 = x^(8/3)

(x^5)^(1/3) = x^(5/3

-4 x^(8/3) y^(5/3)
not quite

∛-64 = -4 (8 is √64)
also, you need to divide both exponents by 3. 8=3*2+2 and 5=3+2
so, the answer is

-4x^2y ∛(x^2y^2)
Similar Questions
  1. Could you please help me with some math problems? Thanks!Add or subtract terms wherever possible. 1. 2 cube root of 135 + cube
    1. answers icon 0 answers
  2. Which expression simplifies to 87–√3?(1 point) Responses −67–√3−27–√3 negative 6 cube root of 7 minus 2 cube
    1. answers icon 1 answer
  3. Simplify:5(cube root of 16) + 2(cube root of 54) 5 times the cube root of 16 plus 2 times the cube root of 54. I do not know how
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions