-64 = -4*-4*-4 = -4^3
(x^8)^1/3 = x^(8/3)
(x^5)^(1/3) = x^(5/3
-4 x^(8/3) y^(5/3)
cube root of (-64x^8y^5)
Is it -8x^2y times the cube of y^2?
2 answers
not quite
∛-64 = -4 (8 is √64)
also, you need to divide both exponents by 3. 8=3*2+2 and 5=3+2
so, the answer is
-4x^2y ∛(x^2y^2)
∛-64 = -4 (8 is √64)
also, you need to divide both exponents by 3. 8=3*2+2 and 5=3+2
so, the answer is
-4x^2y ∛(x^2y^2)