The balanced molecular equation follows:
Cu(NO3)2(aq) + K2S(aq) ==> CuS(s) + 2KNO3(aq)
Here is what you do. Separate the aq solutions into ions.This will give you the TOTAL ionic equation.
Cu(NO3)2(aq) + K2S(aq) ==> CuS(s) + 2KNO3(aq)
Cu^2+(aq) + 2(NO3)^-(aq) + 2K^+(aq) + S^2-(aq) ==> CuS(s) + 2K^+(aq) + 2(NO3)^-(aq)
Now you cancel those ions that appear in both sides of the equation. I see 2(NO3)^-(aq) and 2K^+(aq). That leaves the NET ionic equation.
Cu^2+(aq) + S^2-(aq) ==> CuS(s)
The three steps are as follows:
1. Write and balance the molecular equation.
2. Separate in ions showing (aq) for those in solution and (s) for a ppt. This gives you the total ionic equation.
3. Cancel materials that appear on both sides of the equation. That gives you the net ionic equation. Do you know what those canceled ions are called. Those are spectator ions; they don't enter nor are they needed to make the equation work. ANY Cu^2+ soluble salt (in this case it was nitrate ion) + ANY soluble sulfide (in this case K2S) will give you CuS.
Cu(NO3)2(aq) and K2S(aq)
Express your answer as a net ionic equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is formed.
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