[Cu(H2O)6]2+ (aq) + 2OH- --> Cu(OH)2 (s) + 6 H2O (l)

Question

What would the full equation be for this, rather than the ionic one?

I understand that OH- becomes NaOH but where does the Na go on the right hand side? Thanks

Answer 1

It goes with whatever anion you added to the [Cu(H2O)6]^2+ (i.e., chloride, bromide, sulfate, etc.