csc^4-cot^4= 1+cos^2/sin^2

i need help! please help me

2 answers

LS = (csc^2 Ø + cot^2 Ø)(csc^2 Ø - cot^2 Ø
= (1 + cot^2 Ø + cot^2 Ø)(1+cot^2 Ø - cot^2 Ø
= 1 + 2cot^2 Ø

RS = (1 + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + cos^2 Ø + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + 2cos^2 Ø)/sin^2 Ø
= 1 + 2 cot^2 Ø
= LS
forgot to mention that you cannot just skip the "angle" after a trig operator.
What you typed would be like having an equation of the type ...

√ = ∫ + ∑