The genotypes of the offspring would depend on the specific genotypes of the parents. However, assuming that the heterozygous black rabbit has the genotype Bb and the homozygous black rabbit has the genotype BB, the possible genotypes and phenotypes of the offspring can be determined using Punnett square analysis.
The Punnett square for crossing Bb (heterozygous black) with BB (homozygous black) would look like:
B B
-------------------
B| BB BB
b| Bb Bb
From the Punnett square, it can be observed that there are two possible genotypes (BB and Bb) and two possible phenotypes (black) for the offspring.
If one parent is heterozygous black (Bb) and the other is homozygous black (BB), then the expected genotypes and phenotypes can be:
- Genotype: 2 BB (homozygous black) and 2 Bb (heterozygous black)
- Phenotype: All offspring would have the black color phenotype.
crosses a heterozygous black rabbit with a homozygous black rabbit.
The genotype of offspring (give a number of each genotype) Phenotype of offspring (give the color of the phenotype(s))
1 answer
1 answer