Create the system of inequalities that models the following situation. The field hockey team at school is hosting a fundraiser. They hope to raise at least $600. They are selling chocolate bars for $4 each and flowers for $5 each. The team captain estimates they will sell no more than 150 items. What are the two equations that model the situation? Let x represent the number of chocolate bars, and let y represent the number of flowers sold.(1 point)

Question

Responses

4
x
+
5
y
≤
600
and
x
+
y
<
150
4 x plus 5 y less-than-or-equal-to 600 and x plus y less than 150

5
x
+
4
y
≤
150
and
x
−
y
>
150
5 x plus 4 y less-than-or-equal-to 150 and x minus y greater-than 150

4
x
+
5
y
≥
600
and
x
+
y
≤
150
4 x plus 5 y greater-than-or-equal-to 600 and x plus y less-than-or-equal-to 150

4
x
+
5
y
>
600
and
x
+
y
<
150

Answer 1

To model the situation for the field hockey team's fundraiser, we need to establish two inequalities based on the information provided:

1. The first inequality represents their goal to raise at least $600 by selling chocolate bars and flowers. Since chocolate bars sell for $4 each and flowers for $5 each, this can be expressed as: \[ 4x + 5y \geq 600 \] where \(x\) is the number of chocolate bars and \(y\) is the number of flowers sold.

2. The second inequality represents the limitation on the total number of items sold, which is no more than 150 items: \[ x + y \leq 150 \]

Thus, the correct system of inequalities that models the situation is: \[ 4x + 5y \geq 600 \quad \text{and} \quad x + y \leq 150 \]

Correct Answer: 4 x + 5 y ≥ 600 and x + y ≤ 150.