hole at x=5
y = a(x-5)/(x-5)
vertical asymptote at x=-4
y = a(x-5) / (x-5)(x+4)
x-int at x=3
y = a(x-5)(x-3) / (x-5)(x+4)
horizontal asymptote at y=2
y = 2(x-5)(x-3) / (x-5)(x+4)
Create a rational function that has a hole at x=5, a vertical asymptote at z=-4, a x-int at x=3 and a horizontally asymptote at y=2
1 answer