To analyze the quadratic function \( y = x^2 - 8x \), we can identify the key points: the vertex, x-intercepts, and y-intercept.
1. Finding the Vertex: The vertex of a quadratic in the form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \).
Here, \( a = 1 \) and \( b = -8 \): \[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
Now, substitute \( x = 4 \) back into the original equation to find \( y \): \[ y = (4)^2 - 8(4) = 16 - 32 = -16 \]
So, the vertex is \( (4, -16) \).
2. Finding the x-intercepts: To find the x-intercepts, set \( y = 0 \): \[ 0 = x^2 - 8x \] Factoring gives: \[ 0 = x(x - 8) \] Setting each factor to zero gives: \[ x = 0 \quad \text{or} \quad x = 8 \]
Thus, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
3. Finding the y-intercept: To find the y-intercept, set \( x = 0 \): \[ y = (0)^2 - 8(0) = 0 \]
So the y-intercept is \( (0, 0) \).
Summary of Key Points:
- Vertex: \( (4, -16) \)
- x-intercepts: \( (0, 0) \) and \( (8, 0) \)
- y-intercept: \( (0, 0) \)
Based on the analysis above, the correct response from your options would be:
- x-intercepts: (0,0) and (8,0)
- y-intercept: (0,0)
- vertex: (4,−16)