To analyze the function \( y = x^2 - 8x \), we can find its key points, including the vertex, x-intercepts, and y-intercept.
-
Finding the Vertex: The vertex of a quadratic function in the form \( y = ax^2 + bx + c \) can be found using the formula for the x-coordinate of the vertex, \( x = -\frac{b}{2a} \).
- Here, \( a = 1 \) and \( b = -8 \).
- So, \( x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \).
- To find the y-coordinate of the vertex, substitute \( x = 4 \) back into the equation: \[ y = (4)^2 - 8(4) = 16 - 32 = -16. \]
- Therefore, the vertex is \( (4, -16) \).
-
Finding the X-Intercepts: The x-intercepts occur where \( y = 0 \). So we set the equation to zero: \[ 0 = x^2 - 8x. \] Factoring this gives: \[ x(x - 8) = 0. \] Thus, \( x = 0 \) or \( x = 8 \). The x-intercepts are:
- \( (0, 0) \) and \( (8, 0) \).
-
Finding the Y-Intercept: The y-intercept occurs where \( x = 0 \): \[ y = 0^2 - 8(0) = 0. \] Therefore, the y-intercept is \( (0, 0) \).
Conclusion:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
Considering the options provided, the correct annotations would be:
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Vertex: \( (4, -16) \)
- Y-intercept: \( (0, 0) \)
Thus, a correct response would be: x-intercepts: (0,0) (8,0), vertex: (4,−16), y-intercept: (0,0).