To analyze the function \( y = x^2 - 8x \), we can rewrite it in vertex form to identify key points such as the vertex, x-intercepts, and y-intercept.
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Vertex: To find the vertex, we can complete the square or use the vertex formula. The vertex of a parabola in the form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \).
Here, \( a = 1 \) and \( b = -8 \): \[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \] Substitute \( x = 4 \) back into the function to find the y-coordinate: \[ y = (4)^2 - 8(4) = 16 - 32 = -16 \] Thus, the vertex is \( (4, -16) \).
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X-intercepts: To find the x-intercepts, set \( y = 0 \): \[ 0 = x^2 - 8x \] Factoring gives: \[ 0 = x(x - 8) \] This yields: \[ x = 0 \quad \text{or} \quad x = 8 \] Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
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Y-intercept: To find the y-intercept, set \( x = 0 \): \[ y = 0^2 - 8(0) = 0 \] Thus, the y-intercept is \( (0, 0) \).
Summary of Key Points
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
Among the provided answers, the correct correspondence is:
x-intercepts: \( (0,0) \) and \( (8,0) \)
y-intercept: \( (0,0) \)
vertex: \( (4,-16) \)