To analyze the quadratic function \( y = x^2 - 8x \), we first need to identify the key points, including the vertex, x-intercepts, and y-intercept.
1. Vertex
The vertex of a quadratic function in the form \( y = ax^2 + bx + c \) can be found using the vertex formula: \[ x = -\frac{b}{2a} \] For our equation, \( a = 1 \) and \( b = -8 \): \[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \] To find the corresponding \( y \)-coordinate, substitute \( x = 4 \) back into the equation: \[ y = (4)^2 - 8(4) = 16 - 32 = -16 \] Thus, the vertex is \( (4, -16) \).
2. X-Intercepts
X-intercepts occur where \( y = 0 \). So we set the equation equal to zero: \[ 0 = x^2 - 8x \] Factoring gives us: \[ 0 = x(x - 8) \] Setting each factor to zero gives us: \[ x = 0 \quad \text{or} \quad x = 8 \] Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
3. Y-Intercept
The y-intercept occurs when \( x = 0 \): \[ y = (0)^2 - 8(0) = 0 \] Thus, the y-intercept is \( (0, 0) \).
Summary
- Vertex: \( (4, -16) \)
- X-Intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-Intercept: \( (0, 0) \)
Based on the analysis, the correct response would be:
- x-intercepts: \( (0, 0) \) and \( (8, 0) \)
- y-intercept: \( (0, 0) \)
- vertex: \( (4, -16) \)
Thus, there are two possible answers:
- Correct Option: \( x \)-intercepts: \( (0, 0) \) and \( (8, 0) \), y-intercept: \( (0, 0) \), vertex: \( (4, -16) \)