Asked by Hana blanie

Create a graph; then answer the following question.

What are the key points on the graph of y=x2−8x? Name the vertex, x-intercept(s), and y-intercept.

(1 point)
Responses

x-intercepts: (0,0) (0,8)

vertex: (4,−16)

There is no y-intercept.

x -intercepts: left parenthesis 0 comma 0 right parenthesis left parenthesis 0 comma 8 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis There is no y -intercept.

x-intercept: (4,−16)

y-intercept: (0,0)

vertex: (8,0)

x -intercept: left parenthesis 4 comma negative 16 right parenthesis y -intercept: left parenthesis 0 comma 0 right parenthesis vertex: left parenthesis 8 comma 0 right parenthesis

x-intercept: (0,8)

y-intercept: (0,0)

vertex: (4,−16)

x -intercept: left parenthesis 0 comma 8 right parenthesis y -intercept: left parenthesis 0 comma 0 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis

x-intercepts: (0,0) (8,0)

y-intercept: (0,0)

vertex: (4,−16)

x -intercepts: left parenthesis 0 comma 0 right parenthesis left parenthesis 8 comma 0 right parenthesis y -intercept: left parenthesis 0 comma 0 right parenthesis vertex: left parenthesis 4 comma negative 16 right parenthesis

Answers

Answered by GPT-4o mini
To analyze the quadratic function \( y = x^2 - 8x \), we first need to identify the key points, including the vertex, x-intercepts, and y-intercept.

### 1. Vertex
The vertex of a quadratic function in the form \( y = ax^2 + bx + c \) can be found using the vertex formula:
\[
x = -\frac{b}{2a}
\]
For our equation, \( a = 1 \) and \( b = -8 \):
\[
x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4
\]
To find the corresponding \( y \)-coordinate, substitute \( x = 4 \) back into the equation:
\[
y = (4)^2 - 8(4) = 16 - 32 = -16
\]
Thus, the vertex is \( (4, -16) \).

### 2. X-Intercepts
X-intercepts occur where \( y = 0 \). So we set the equation equal to zero:
\[
0 = x^2 - 8x
\]
Factoring gives us:
\[
0 = x(x - 8)
\]
Setting each factor to zero gives us:
\[
x = 0 \quad \text{or} \quad x = 8
\]
Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).

### 3. Y-Intercept
The y-intercept occurs when \( x = 0 \):
\[
y = (0)^2 - 8(0) = 0
\]
Thus, the y-intercept is \( (0, 0) \).

### Summary
- **Vertex**: \( (4, -16) \)
- **X-Intercepts**: \( (0, 0) \) and \( (8, 0) \)
- **Y-Intercept**: \( (0, 0) \)

Based on the analysis, the correct response would be:
- **x-intercepts**: \( (0, 0) \) and \( (8, 0) \)
- **y-intercept**: \( (0, 0) \)
- **vertex**: \( (4, -16) \)

Thus, there are two possible answers:
- **Correct Option**: \( x \)-intercepts: \( (0, 0) \) and \( (8, 0) \), y-intercept: \( (0, 0) \), vertex: \( (4, -16) \)
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